多家公司相关的笔试题目汇总

北京信威通信技术股份有限公司面试题
　　1．DSP和通用处理器在结构上有什么不同？请简要画出你熟悉的一种DSP结构图。
　　2．说说定点DSP和浮点DSP的定义（或者说出他们的区别）。
　　3．说说你对循环寻址和位反序寻址的理解。
　　4．请写出【8，7】的二进制补码和二进制偏置码。用Q15表示出0.5和ɦ
85;0.5。

中国国际金融有限公司CICC笔试题
　　1. Please tell us about an achievement that you are especially proud of be
cause it was difficult or demanding.
　　（1）What the objective was?
　　（2）Why it is important to you?
　　（3）How you achieved it and the obstacles that you had to overcome in ord
er to do so?
　　2. What is your career plan? Three years after graduation, and five years
after graduation?
　　3. Why are you interested in investment bank? What other industries do you
also have interests?
　　4. Why do you think you can be a qualified investment banker? How can you
contribute in this industry?

国泰君安笔试题
　　一列火车上有三个工人，史密斯、琼斯和罗伯特，三人工作为消防员、司闸员和机械
师，有三个乘客与这三人的名字相同。罗伯特住在底特律；司闸员住在芝加哥和底特律中
间的地方；琼斯一年赚2万美金；有一个乘客和司闸员住在一个地方，每年的薪水是司闸员
的3倍整；史密斯台球打得比消防员好；和司闸员同名的乘客住在芝加哥。
　　请问谁是机械师？

Briny笔试题
　　1．说出RC振荡器的构成和工作原理。
　　2．什么是SDH?
　　3．什么是共模、差模?画出差分电路的结构。
　　4．a=5; b=6; a+=b++; 执行结果是什么？
　　5．什么是TDM？什么是CDMA？
　　6．什么是采样定理？
　　7．什么是香农定理？
　　8．计算机的中断有哪几类？

广东北电面试题目
　　英文笔试题
　　1. Tranlation (Mandatory)
　　CDMA venders have worked hard to give CDMA roaming capabilities via the de
velopment of RUIM-essentially, a SIM card for CDMA handsets currently being de
ployed in China for new CDMA operator China Unicom. Korean cellco KTF demonstr
ated earlier this year the ability to roam between GSM and CDMA using such car
ds.However,only the card containing the user’s service data can roam-not the
CDMA handset or the user’s number (except via call forwarding).
　　2. Programming (Mandatory)
　　Linked list
　　a. Implement a linked list for integers,which supports the insertafter (in
sert a node after a specified node) and removeafter (remove the node after a s
pecified node) methods;
　　b. Implement a method to sort the linked list to descending order.
　　3. Debugging (Mandatory)
　　a. For each of the following recursive methods,enter Y in the answer box i
f themethod terminaters (assume i=5), Otherwise enter N.
　　static int f(int i){
　　 return f(i-1)*f(i-1);
　　 }
　　Ansewr:
　　static int f(int i){
　　 if(i==0){return 1;}
　　 else {return f(i-1)*f(i-1);}
　　 }
　　Ansewr:
　　static int f(int i){
　　 if(i==0){return 1;}
　　 else {return f(i-1)*f(i-2);}
　　 }
　　Ansewr:
　　b. There are two errors in the following JAVA program:
　　static void g(int i){
　　 if(i==1){return;}
　　 if(i%2==0){g(i/2);return;}
　　 else {g(3*i);return;}
　　 }
　　please correct them to make sure we can get the printed-out result as belo

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